In MATH 106 we have been studying uses of the Pythagorean Theorem in order to measure things with arcs, such as suspension bridges or bowed railroad tracks. Basic geometry, not too difficult:



So, in Thursday night's homework, there was this word problem:
"A 150-foot rope is suspended at its two ends from the tops of two 100-foot flagpoles. The lowest point of the rope is 25 feet from the ground. What is the distance between the two flagpoles?"

It seemed pretty straightforward, not much different than any of the other homework problems I had been working on. So I drew myself a little diagram, so that I could visualize the solution:


Based upon the values given, I could determine that:

Now I knew that c was actually a little less than 75ft, because of the sag in the rope. But we were instructed by our textbook to do these kinds of problems this way, knowing that there would be a little bit of error built in. Normally for these kinds of problems, it works pretty well. (Though not this time).

With the values of b and c known, I can now solve for a, which I know to be 50% of the length of the distance between the two flagpoles. In other words, the distance between the two flagpoles is 2 times the value of a.

So I plug my values into the Pythagorean Theorem. Since I am solving for a, I rewrite the formula, and solve:



Uh oh... a2 is the square root of zero? That can't be right. Something is very, very wrong here!

I go back and re-do all my calculations. I double check everything. I re-read the problem. I re-evaluate my initial assumptions. I even re-draw the diagram!

And every time I get the same result!

I ended up spending almost 2 hours on this one problem Thursday night, and didn't end up getting to bed until almost 2 am because of it. I had completed all of the rest of the homework assignment, except for this one problem. So I finally decided just to sleep on it.

Friday morning before class, I went into the Learning Resource Center on campus and asked for a math tutor's help. A nice guy who had helped me before sat down with me, and listened as I explained the problem to him. We went over the instructions in the textbook on how to solve this kind of problem. He went over all of my calculations... and came up with the same results as I did!

He went and got another tutor, who also went over all my work... and came up with the same thing. What was going on here?

The second tutor said, "Despite the fact that the book is telling you to solve the problem this way, I don't think this problem is solvable with the Pythagorean Theorem."

So, now having spent more than 4 hours of time on this one stupid homework word problem, I went to class, prepared to confront the TA who teaches the class.

Turns out I wasn't the only one who was stumped by this problem.

I asked the instructor to show us how to use the Pythagorean Theorem to solve this word problem. Her response:

You don't need use it to solve this problem.

The only way you can have a 150ft rope, suspended between two flagpoles, where the rope hangs down to 25 ft above the ground is...

(Are you ready for this?)

...If the flagpoles are standing right next to each other, with no distance between them.


D'OH!

You know, for someone who prides himself on being able to think outside the box, I didn't see that one coming.

I mean, in hindsight, the math told me that the distance between the two flagpoles was zero (2 times a, with a being the square root of zero)!

But neither I, nor the two tutors helping me, nor half my classmates, were able to make the intuitive leap from that unexpected result to the actual truth.

I hate trick questions.

Especially when I get them wrong.

From: [identity profile] detailbear.livejournal.com


What tipped me off that there was a problem was that the hypoteneuse and the height of the triangle were both about 75 feet. Visualizing that, the distance (a) had to be very short. The hypoteneuse has to be the largest number.

But yeah, it's a trick question, especially if they don't teach "first, determine if this is a question that uses the Pythagorean theorem".

From: [identity profile] kevynjacobs.livejournal.com


I've never taken Geometry, and I don't think I have ever done any work with the Pythagorean Theorem before this week.... so I had no idea what to expect, and didn't know that the hypoteneuse (that's c, right?) is has to be longer than the other two sides. But I can atribute it to ignorance... what about the tutors?

What, no comments on my cool Canadian flags I used for the illustration? ;-)

From: [identity profile] kc-risenphoenix.livejournal.com


This is why I don't do math. I would have been SOOO mad I would have gone into afib again and would have had to been rushed to the hospital. I wonder then when would have been the next time the teacher pulled that...

From: [identity profile] detailbear.livejournal.com


Yup, it's c. Over on Wikipedia, the Pythagorean Theorem is given as:
In any right triangle, the area of the square whose side is the hypotenuse (the side of a right triangle opposite the right angle) is equal to the sum of areas of the squares whose sides are the two legs (i.e. the two sides other than the hypotenuse).


And I'm kind or surprised that isn't how they taught it.

And the Canadian flags were noticed, but hardly noteworthy coming from you. ;-)

From: [identity profile] kevynjacobs.livejournal.com


>And I'm kind or surprised that isn't how they taught it.
Actually, they didn't teach it at all. Just said, "This is the Pythagorean Theorem, this is how you use it to solve these kinds of problems." I think there was an assumption that it had been studied at an earlier point in one's academic career - but in my case, it hadn't been.

> And the Canadian flags were noticed, but hardly noteworthy coming from you. ;-)

Alas, my love for Canada has become so cliché, not even my Canadian friends make note anymore when I sneak references to Canada into my presentations...

From: [identity profile] detailbear.livejournal.com


In fact, if you had used a U.S. flag, I would probably have said something.
.

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